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python密码错误3次不能再输入(Python实现账号密码输错三次即锁定功能简单示例)

更多 时间:2021-10-24 10:03:58 类别:脚本大全 浏览量:2768

python密码错误3次不能再输入

Python实现账号密码输错三次即锁定功能简单示例

本文实例讲述了Python实现账号密码输错三次即锁定功能。分享给大家供大家参考,具体如下:

初学Python—1

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  • #实现账号输错三次即锁定
  • user = "hubery"
  • passwd = "123"
  • confirm = 0
  • lock=0
  • fileOpen = open("username.txt","a+")
  • fileOpen.seek(0)
  • for i in range(3):
  •  username = input("username:")
  •  passsword = input("password:")
  •  for line in fileOpen.readlines():
  •   if username == line.strip():
  •    print("账户已经锁定!")
  •    lock=1
  •    break
  •   else:
  •    continue
  •  fileOpen.seek(0)
  •  if user == username and lock ==0:
  •   if passwd == passsword:
  •    print("欢迎,欢迎!")
  •    confirm = 1
  •    break
  •   else:
  •    print("账号户或者密码错误!")
  •    continue
  •  elif lock==1:
  •   continue
  •  else:
  •   print("1账号或者密码错误!")
  •   continue
  • fileOpen.close()
  • if confirm == 0 and lock==0:
  •  fileWrite=open("username.txt","a")
  •  fileWrite.write(username+"\n")
  •  fileWrite.close()
  • 基本功能可以实现;

    锁定的账号为第三次输错的用户名(待完善)

    以下为完善版本,如有错误,请告知

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  • import os
  • user = "hubery"
  • passwd = "123"
  • count = 0
  • lock = 0
  • fileOpen = open("username.txt", "a+")
  • fileOpen.seek(0)
  • while 1:
  •  for i in range(5):
  •   username = input("username:")
  •   passsword = input("password:")
  •   for line in fileOpen.readlines():
  •    if username == line.strip():
  •     print("账户已经锁定!")
  •     lock = 1
  •     break
  •    else:
  •     continue
  •   fileOpen.seek(0)
  •   if user == username:
  •    if lock == 1:
  •     continue
  •    elif passsword == passwd:
  •     print("欢迎,欢迎!")
  •     os._exit(0)
  •    elif count < 2:
  •     print("账号或者密码错误!")
  •     count += 1
  •     continue
  •    else:
  •     fileOpen.write(username + "\n")
  •     fileOpen.flush()
  •     print("密码输入错误超过三次,账户已经锁定!")
  •     fileOpen.seek(0)
  •     continue
  •   else:
  •    print("账号密码错误!")
  •    continue
  •  check=input("还想验证其他账户?(yes-继续,no-退出)")
  •  if "no"==check.lower():
  •   os._exit(0)
  •  else:
  •   continue
  • fileOpen.close()
  • 希望本文所述对大家Python程序设计有所帮助。

    原文链接:https://blog.csdn.net/sen1013293436/article/details/64545220

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